Decoding JSON with a reserved property name

Question

Created Jul ’24

Replies 2

Boosts 0

Participants 3

I need to decode JSON into a class. The JSON has a field called "Type", and I cannot declare a property with that name in my class since Type is a reserved word.

I tried declaring CodingKeys, but that doesn't work unless I declare EVERY property in the CodingKeys. This class has about a hundred properties and I have others like it, I do not want to do this.

Is there a better solution?

Boost

Answer 1

darkpaw OP

Jul ’24

Have you tried using backticks?

var `Type`: String

1

Answer 2

Engineer OP

Apple

Jul ’24

Coding keys are recommended. You can use some form of API code generation with an endpoint or API spec to generate the code for you if 100+ keys are too much to type.

0