How to handle predicate with optionals in SwiftData

Question

m4rqs OP

Created Dec ’23

Replies 4

Boosts 1

Views 1.5k

Participants 3

Xcode: 15.1

I've got (simplified) model with relationship many-to-many defined as follows

@Model
final class Item {
    var title: String
    @Relationship(inverse: \Tag.items) var tags: [Tag]?

    init(_ title: String) {
        self.title = title
    }
}

@Model
final class Tag {
    var name: String
    var items: [Item]?

    init(_ name: String) {
        self.name = name
    }
}

and a view with a query

struct ItemsView: View {
    @Query var items: [Item]

    var body: some View {
        List {...}
    }

    init(searchText: String) {
        _items = Query(filter: #Predicate<Item> { item in
            if (searchText.isEmpty) {
                return true
            } else {
                return item.tags!.contains{$0.name.localizedStandardContains(searchText)}
            }
        })
    }
}

This code compiles but fails at runtime with an error: Query encountered an error: SwiftData.SwiftDataError(_error: SwiftData.SwiftDataError._Error.unsupportedPredicate)

It looks like Predicate does not like optionals cause after changing tags and items to non optionals and the predicate line to

item.tags.contains{$0.name.localizedStandardContains(searchText)}

everything works perfectly fine.

So, my question is, does anybody know how to make it work with optionals?

Full code: https://github.com/m4rqs/PredicateWithOptionals.git

Answered by thibautrichez in 774913022

Sorry, I wasn't able to test my answer earlier and was confident that this kind of query worked but I end up with the same error: to-many key not allowed here. I tried other alternatives but couldn't find one that worked. Doesn't seem like it's possible to use optional to-many relationships inside a Predicate (even checking for $0.tags != nil or similar will crash)

A workaround would be to query on the to-one side of the relationship, i.e Tag and compute the array of Item from the results. It's not ideal but I couldn't find another way. Since it's working for non-optional relationships we can only hope that this will possible in future releases.

struct ItemsView: View {
    @Query private var tags: [Tag]

    var items: [Item] {
        self.tags.lazy.compactMap(\.items).flatMap { $0 }
    }

    init(searchText: String) {
        self._tags = Query(filter: #Predicate<Tag> {
            $0.name.localizedStandardContains(search)
        })
    }
}

Boost

Answer 1

thibautrichez OP

Dec ’23

As stated in the thread 742807, you should not force unwrap your properties inside the predicate. You could use flatMap to access the unwrapped array of tags

    init(searchText: String) {
        _items = Query(filter: #Predicate<Item> {
            if searchText.isEmpty {
                true
            } else {
                $0.tags.flatMap {
                    $0.contains { $0.name.localizedStandardContains(searchText) }
                } == true
            }
        })
    }

0

Answer 2

m4rqs OP

Dec ’23

Thanks for the answer. Unfortunately this doesn't work. It falls over with "to-many key not allowed here" error.

0

Answer 3

thibautrichez OP

Dec ’23

Accepted Answer

Sorry, I wasn't able to test my answer earlier and was confident that this kind of query worked but I end up with the same error: to-many key not allowed here. I tried other alternatives but couldn't find one that worked. Doesn't seem like it's possible to use optional to-many relationships inside a Predicate (even checking for $0.tags != nil or similar will crash)

A workaround would be to query on the to-one side of the relationship, i.e Tag and compute the array of Item from the results. It's not ideal but I couldn't find another way. Since it's working for non-optional relationships we can only hope that this will possible in future releases.

struct ItemsView: View {
    @Query private var tags: [Tag]

    var items: [Item] {
        self.tags.lazy.compactMap(\.items).flatMap { $0 }
    }

    init(searchText: String) {
        self._tags = Query(filter: #Predicate<Tag> {
            $0.name.localizedStandardContains(search)
        })
    }
}

3

Answer 4

m4rqs OP

Dec ’23

Thank you so much. It worked. This really puzzles me as the documentation https://developer.apple.com/documentation/foundation/predicate says that swift optionals can be freely used with predicates.

0